{"id":1885,"date":"2017-12-26T22:33:33","date_gmt":"2017-12-26T11:33:33","guid":{"rendered":"http:\/\/casestudyhelp.com\/sample-questions\/?p=1885"},"modified":"2019-09-20T20:57:57","modified_gmt":"2019-09-20T10:57:57","slug":"matlab-programming-assignment-on-engineering-simulations-and-computations-12","status":"publish","type":"post","link":"https:\/\/casestudyhelp.com\/sample-questions\/matlab-programming-assignment-on-engineering-simulations-and-computations-12\/","title":{"rendered":"MATLAB Programming Assignment on Engineering Simulations and Computations 1,2"},"content":{"rendered":"

Q 1\u00a0\u00a0 \u00a0(worth 115 marks)<\/strong><\/h2>\n

1.1\u00a0\u00a0 \u00a0Introduction<\/strong><\/p>\n

Further analysis of the viaduct from Assignment 3 Question 3 is to be performed. An important reason for the construction of the Range Crossing is to reduce the gradient of the road for trucks. You will analyse the data in ass4q1in.csv to calculate gradients of the road with and without the viaduct. For this question, we are assuming that the viaduct follows a straight line between its end-points and the\u00a0x<\/em>-coordinate has been reoriented to act along the length of the bridge.<\/p>\n

1.2\u00a0\u00a0 \u00a0Requirements<\/strong><\/p>\n

For this assessment item, you must perform hand calculations:<\/p>\n

1.<\/strong>\u00a0Assuming that there is no viaduct, estimate the value of the gradient\u00a0\u2202z\/\u2202x\u00a0<\/em>at the second measurement point using backward, forward and central differences.<\/p>\n

2.<\/strong>\u00a0Discuss which is the best result out of the backward, forward and central differences and why.<\/p>\n

3.<\/strong>\u00a0Estimate the overall gradient of the viaduct. You must also produce MATLAB code which:<\/p>\n

4.<\/strong>\u00a0Calculates backward, forward and central differences for\u00a0\u2202z\/\u2202x\u00a0<\/em>for the length of the road, assuming there is no viaduct. The calculations should be for each possible section (you will not calculate differences for every value of\u00a0x<\/em>).<\/p>\n

5.<\/strong>\u00a0Verifies the results from Requirement 4 using the results of Requirement 1.<\/p>\n

6.<\/strong>\u00a0**Estimates the numerical error in the calculations of Requirement 4. Perform this using numerical derivatives for as many data points as possible; at the ends of the data, use the value closest to the end (e.g. for the 1st datum, use the second derivative calculated at the 2nd datum, and the third derivative calculated at the 3rd datum). \u00a0For data spaced evenly in\u00a0x<\/em>, the necessary formulae are [the methods are\u00a0O<\/em>(\u2206x<\/em>2) accurate]:<\/p>\n

For data unevenly \u00a0spaced in\u00a0x<\/em>, the necessary formulae are [the methods are\u00a0O<\/em>(\u2206x<\/em>) accu- rate]:<\/p>\n

7.<\/strong>\u00a0Plots the results from Requirements 4 and 6. Also plots\u00a0\u2202z\/\u2202x\u00a0<\/em>(correct Requirement 4 us- ing Requirement 6) together with the central difference from Requirement 4. On the plots of the gradient, also show the viaduct average gradient. Discusses the results, including which is the best method.<\/p>\n

8.<\/strong>\u00a0Has appropriate comments throughout.<\/p>\n

1.3\u00a0\u00a0 \u00a0Assessment Criteria<\/strong><\/p>\n

Your code will be assessed using \u00a0the following scheme. Note that you are marked based on how well you perform for each category, \u00a0so the correct answer determined in a basic way will receive half marks and the correct answer determined using an excellent method\/code will receive full marks.<\/p>\n\n\n\n\n\n\n\n\n\n
Quality of hand calculations<\/td>\n30 marks<\/td>\n<\/tr>\n
Quality of difference calculations<\/td>\n30 marks<\/td>\n<\/tr>\n
Quality of verification<\/td>\n5 marks<\/td>\n<\/tr>\n
Quality of error calculations<\/td>\n30 marks<\/td>\n<\/tr>\n
Quality of the plots<\/td>\n10 marks<\/td>\n<\/tr>\n
Quality of the discussion<\/td>\n5 marks<\/td>\n<\/tr>\n
Quality of header(s) and comments<\/td>\n5 marks<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n